3x^2-35x+32=0

Solution for 3x^2-35x+32=0 equation:

3x^2-35x+32=0

a = 3; b = -35; c = +32;
Δ = b2-4ac
Δ = -352-4·3·32
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-29}{2*3}=\frac{6}{6}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+29}{2*3}=\frac{64}{6}
=10+2/3
$